Q (heat) = M*C*(delta T)
= 100,000 g * 1.00 cal/g C * 15 deg
= ? cal
To get the answer in Joules, multiply the number of calories by 4.18
if you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in calories and joules)
2 answers
150000