[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for specific heat
metal.
a 5.0 x 10^1g piece of a metal in thermal equilibrium with boiling water is removed and placed in 1.0 x 10^2g of a cooling water bath (specific heat= 1.00cal/g degrees celsius at 20.0 degrees Celsius . The final temperature of metal and the water bath is 28.0 degrees celsius What is the specific heat of the metal?
1 answer
1 answer