You can answer a) after following the process shown in this post.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Then part b can be answered knowing that moles = M x L.
If you react 25.25 g of Na2CO3 with 50.0 mL of 6.0M HCl, answer the following questions:
Na2CO3 + 2 HCl -> 2 NaCl + H2O + CO2
question:
a) How many moles of HCl do you need to react completely with the 25.25 g of NaCO3?
b) What is limiting reagent?
1 answer