If you launch a firework and it does not explode, but it lands after 9.572 seconds make a table for the situation so that it shows the height from time T equals zero until it hits the ground.

Answer 1

To create a table displaying the height of the firework from time 0 until it hits the ground after 9.572 seconds, we can use the equations of motion. Let's assume the initial height of the firework is H0 and that it is launched vertically upwards.

We know that the equation describing the height of an object in terms of time is given by:

h(t) = H0 + v0*t + (1/2)*a*t^2,

Where:
h(t) is the height at time t,
H0 is the initial height (time t = 0)
v0 is the initial velocity (at time t = 0)
a is the acceleration due to gravity (approximately -9.8 m/s^2).

Since the firework launches vertically upwards, its initial velocity will be positive.

Assuming the initial height H0 is known, we can create a table to show the height of the firework at various times until it hits the ground after 9.572 seconds.

Here's an example table (assuming H0 = 100 meters):

| Time (s) | Height (m) |
|----------|------------|
| 0.0 | 100.0 |
| 1.0 | 100.0 |
| 2.0 | 100.0 |
| 3.0 | 100.0 |
| 4.0 | 100.0 |
| 5.0 | 100.0 |
| 6.0 | 100.0 |
| 7.0 | 100.0 |
| 8.0 | 100.0 |
| 9.0 | 100.0 |
| 9.572 | 0.0 |

In this table, the height remains constant at 100.0 meters until the time of 9.0 seconds, after which the firework reaches its peak and starts to descend. At precisely 9.572 seconds, it reaches the ground, so the height becomes 0.0 meters.