Asked by Rachel
A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel at speeds shown at the right. Firework B is launched 0.25 s before Firework A. How many seconds after Firework B launches will both fireworks explode?
Firework A: 220 ft/s
Firework B: 200 ft/s
Firework A: 220 ft/s
Firework B: 200 ft/s
Answers
Answered by
Steve
when the heights are equal, t seconds after B's launch,
220(t-.25)-16(t-.25)^2 = 220t-16t^2
t = 7.0
220(t-.25)-16(t-.25)^2 = 220t-16t^2
t = 7.0
Answered by
fred
bla
Answered by
NAme
1.25
Answered by
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Answered by
Amelia
2.5
Answered by
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Answered by
Avril
2.75s
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