If you have an insulated glass of water at 25 oC containing 10 fluid oz at 25 oC, how much ice would you have to add to end up with a final temperature of 0 oC and no ice left?

2 answers

Convert 10 oz to grams. There are 28.35 g to an oz.
(mass ice x heat fusion ice) + [(mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for Tfinal, the only unknown. Post your work, IN DETAIL, if you get stuck.
283.5 x .5 + 10 x 1 X (X)=0