if you have 55.6 grams of nitrate ions in a compound that consists of nitrate ions and plumbous ions, how many grams of the compound do you have?

Question

how do i do this problem im completely stuck!?

Answer 1

Pb(NO3)2.

mols NO3^- = 55.6/molar mass NO3^- = ??
mols Pb(NO3)2 = mols NO3^- x (1 mol Pb(NO3)2/2 mols NO3^-) = ??

grams Pb(NO3)2 = mols plumbous nitrate X molar mass plumbous nitrate.

Answer 2

Why two postings of the same question?
You have an answer at:
http://www.jiskha.com/display.cgi?id=1228951921

Answer 3

thanks sorry i posted it again when i didn't get an answer for a long time

thanks again