To predict the percentage of homozygous black-furred guinea pigs resulting from a cross between a homozygous (BB) and a heterozygous (Bb) guinea pig, we can set up a simple Punnett square.
- Parent 1 (homozygous): BB
- Parent 2 (heterozygous): Bb
The alleles from each parent can be combined as follows:
B B
--------
B | BB BB
b | Bb Bb
From this Punnett square, we see the possible genotypes of the offspring:
- BB (homozygous black fur) - 2 squares
- Bb (heterozygous black fur) - 2 squares
Now, let's count the total number of offspring genotypes:
- Total: 4 (2 BB + 2 Bb)
The percentage of homozygous black-furred guinea pigs (BB) would be:
\[ \text{Percentage of BB} = \left( \frac{2 \text{ BB}}{4 \text{ total}} \right) \times 100 = 50% \]
Thus, the predicted percentage of homozygous, black-furred guinea pigs is 50%.
1 answer