If you crossed a homozygous (BB) guinea pig for black fur color with a heterozygous (Bb) guinea pig for black fur color, what would be the predicted percentage of homozygous, black-furred guinea pigs?(1 point)

Responses

100%
100%

50%
50%

75%
75%

25%

1 answer

To determine the predicted percentage of homozygous black-furred guinea pigs from a cross between a homozygous (BB) guinea pig and a heterozygous (Bb) guinea pig, we can use a Punnett square.

The genotypes we have for the two parent guinea pigs are:

  • Parent 1: BB (homozygous)
  • Parent 2: Bb (heterozygous)

The possible gametes from each parent are:

  • Parent 1 (BB): B, B
  • Parent 2 (Bb): B, b

Now we can set up the Punnett square:

       B    |     B
---------------------
   B |  BB  |   BB
---------------------
   b |  Bb  |   Bb

From this Punnett square, we see the following genotypes among the offspring:

  • 2 BB (homozygous black fur)
  • 2 Bb (heterozygous black fur)

To find the percentage of homozygous black-furred guinea pigs (BB), we total the number of homozygous individuals and divide by the total number of offspring:

Total offspring = 2 (BB) + 2 (Bb) = 4

Percentage of homozygous black-furred guinea pigs (BB) = (Number of BB / Total offspring) × 100 = (2 / 4) × 100 = 50%

Therefore, the answer is:

50%