If you are given a 0.32 g piece of sodium metal to react with water, how many moles of HCl would it take to neutralize the sodium hydroxide produced?

Answer 1

2Na + 2H2O ==> H2 + 2NaOH
HCl + NaOH ==> NaCl + H2O

0.32 g Na x (1 mole/23 g Na) = ?? moles Na.

You know from the equation that 2 moles Na will produce 2 moles NaOH (of course 1 mole produces 1 mole) and you know 1 mole HCl reacts with 1 mole NaOH. Therefore, the moles of Na will be the same as the moles of HCl required.

Answer 2

.0139