If x is a positive integer and l2x+6l > 10, what is the least possible value of x?

NOTE: l2x+6l means absolute value of 2x+6

5 answers

l2x+6l > 10
---> 2x+6 > 10 OR -2x-6 > 10
2x > 4 or -2x > 16
x > 2 or x < -8

think of the positive number line, which integer x do you have so that x > 2 ?

this is kind of a solve by inspection (and thought) problem

the "magic" value is 10 ... 2x + 6 must be GREATER than 10 (not equal to)

how small can x (a positive integer) be , if 2x must be greater than 4?

would it be 3??

of course

thank you

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