If velocity v of particle moving in straight line is related with distance travelled S as v=2(1+S)^1/2. What will the acceleration of the particle?

Answer 1

The problem I have here is units.

velocity is distance/time, and your equation is sqrt distance. Hmmmm.

Assuming somehow that is fixed in magic land, then

acceleration= dv/dt=
(1+s)^-1/2 * ds/dt but ds/dt is V so

acceleration= 2 (1+s)^0=2