First you have to find the amount of water (in grams) that will react with 2 mol of phenylmagesium bromine. Then you convert the grams into mg. Finally, you divid by 25.
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If there are 25 mg of water in a typical drop of water, how many drops of water
would react completely with 2 mmol of phenylmagnesium bromide?
How do I set up the problem?
5 answers
How do you find the amount of water that reacted 2 mol of phenylmagesium bromine?
You have to first right the balanced formula
MgBr + H2O --> Benzene + Mg(OH)Br
This means that 2 mols of water will react with 2 moles of phenylmagnesium bromide
MgBr + H2O --> Benzene + Mg(OH)Br
This means that 2 mols of water will react with 2 moles of phenylmagnesium bromide
2 mol of water equals 36 gram or 36000 mg so the answer is 1440 drops of water
But remember it is 2 mmol of water so it is actually 1.44 drops of water