If the vinegar is actually 5.00% by mass acetic acid in water what is your percent error? Percent error =[(actual value- experimental value / actual value)]*100

Answer 1

The actual value for the percent of acetic acid in vinegar is 4.76% (accepted value).

The experimental value given is 5.00%.

Using the formula:

Percent error = [(4.76 - 5.00) / 4.76] * 100
Percent error = [(-0.24) / 4.76] * 100
Percent error = -0.0504 * 100
Percent error = -5.04%

Therefore, the percent error in this case is -5.04%.