if the temperature of a 500.0g sample of liquid water is raised to 2.00c how much heat is absorbed by the water? The specific heat of liquid water is 4.184J/(g*c)

3 answers

q = mass water x specific heat water x (Tfinal - Tinitial)
How much energy must be absorbed by 20.0 g of water to increase its temperature from 43.0 °C to 83.0 °C? (C = 4.184 J/g°C)
200