If the temperature of a 500.0-g sample of liquid water is raised 2.00c how much heat is absorbed by the water?The specific heat of liquid water is 4.184j/(g*c)
4 answers
q = mass H2O x specific heat H2O x delta T
q= c • m • delta T
q= (4.184 J/g*C)(500.0g)(2.00*C)
q= 4184 J
q= (4.184 J/g*C)(500.0g)(2.00*C)
q= 4184 J
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what the answer be doe
3 answers