If the sides of the rectangle are (fq-8)dm and (f^2g^2 + 8fg + 64) dm. what is the area of the rectangle ?

Question

Please Help me :\ and thank you for those who answer :)

Answer 1

(fg-8)(f^2g^2 + 8fg + 64)
This is just the difference of two cubes:
(fg)^3 - 8^3

Recall that
(a^3-b^3) = (a-b)(a^2+ab+b^2)
You have
a = fg
b = 8

Answer 2

a = fg+b = 8