If the reaction of 0.500 grams of aluminum metal with excess aqueous HCl releases 9.72 kJ of heat, what is the ΔH value for the reaction? 2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)

Question

All I have is:
.500gAl*(1 mol Al/26.98gAl)

Please and thank you so much!

Answer 1

I would do it this way. 0.5 g produces 9.72 kJ so how much will you get from 2*26.98?
9.72 kJ x (2*26.98)/0.5) = ?