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if the radius of a sphere is increased by 10%, prove that its volume will be increased by33.1%.
3 answers
V=4/3 ¦Ðr^3
r -> 1.1 r
V=4/3 ¦Ð¡¼(1.1r)¡½^3
V=4/3 ¦Ð x 1.331 r^3
So the increase is .331 or 33.1 %
r -> 1.1 r
V=4/3 ¦Ð¡¼(1.1r)¡½^3
V=4/3 ¦Ð x 1.331 r^3
So the increase is .331 or 33.1 %
How it will come 1.1 or 11/10