If the pth,qth and rth terms of an AP be a,b and c respectively then prove that p(b-c)+q(c-a)+r(a-b)=0

2 answers

If the AP has

1st term=x
difference=y

a = x+(p-1)y
b = x+(q-1)y
c = x+(r-1)y

Now just plug and chug ... and chug ... and chug
Thank a lot!!!:))
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