If the pth,qth and rth terms of an AP be a,b and c respectively then prove that p(b-c)+q(c-a)+r(a-b)=0

Answer 1

If the AP has

1st term=x
difference=y

a = x+(p-1)y
b = x+(q-1)y
c = x+(r-1)y

Now just plug and chug ... and chug ... and chug

Answer 2

Thank a lot!!!:))