If the price of electrical enegy is $0.10 per kilowatt *hour, find the cost of using electrical energy to heat the water in a 12.0m * 9.00m * 1.5m swimming pool from 15 degrees C to 27 degrees C.
So the change in temperature is 285.15 , the volume is 162m^3, the specific heat capacity (c) is 4.186 [J/kg*degrees C]. Please and Thanks.
2 answers
You're not going to get an answer here, I've tried this site, and everytime, I get the wrong answer or no one responds.
The change in temperature is 12 deg C if it rises from 15 to 27 degrees.
1. Find the mass of water from volume of water times its density.
2. Find the heat in Joule needed from Q=mct where m is mass of water, c is specific heat capacity and t is rise in temperature.
Then the cost.
3. One kilowatt hour is
1000W x 60(min) X 60(sec) Joules.
4. Then find how many of these you need to heat that water.
5. Each one costs $0.1
1. Find the mass of water from volume of water times its density.
2. Find the heat in Joule needed from Q=mct where m is mass of water, c is specific heat capacity and t is rise in temperature.
Then the cost.
3. One kilowatt hour is
1000W x 60(min) X 60(sec) Joules.
4. Then find how many of these you need to heat that water.
5. Each one costs $0.1
1 answer