Nope.
If the reaction as written is -56 kJ/mol then it would be -112 kJ for 2 mols and rhe REVERSE of that is +112 kJ/2 mol.
If the following reaction:
NO(g) + 1/2O2(g) NO2(g)
has the following enthalpy change:
H° = -56 kJ/mol
What is the enthalpy of the decomposition reaction of 2 moles of NO2?
A. 112 kJ
B. 56 kJ
C. -56 kJ
D. -112 kJ
i think the answer is d
1 answer