If the first term of AP is 5 and the common difference is -3.Find the 15th term of the sequence

3 answers

a_n = a+(n-1)d
so you want
a_15 = 5 + 14(-3) = ____
a_15=5+14(-3)
15a=-57
15a=-57
a=-3.8
Tn=a+(n -1)d
T15=5+(15 - 1)(-3)
=5+14 (-3)
=5-42=-37