Calculate: The first term of a linear sequence is 5 and the common difference is 3, find the 15th term of the sequence

Answer 1

By the time you finished typing this question, you should have been able to do the arithmetic mentally ....

term(15) = a + 14d
= 5 + 14(3)
= ..

Answer 2

The nth term of a linear sequence is:

an = d ∙ n - c

where

d = common difference

c = constant that you´ll need to calculate

In this case:

a1 = 5 , d = 3 , n = 1

a1 = d ∙ n - c

5 = 3 ∙ 1 - c

5 = 3 - c

Subtract 3 to both sides

2 = - c

Multiply both sides by - 1

- 2 = c

c = - 2

So the nth term of your linear sequence is:

an = d ∙ n - c

an = 3 n - ( - 2 )

an = 3 n + 2

15th term of the sequence:

an = 3 n + 2

where n = 15

a15 = 3 ∙ 15 + 2

a15 = 45 + 2

a15 = 47

Answer 3

The result is the same as Reiny 's but the procedure is a little different.

Answer 4

I don't actually understand

Answer 5

The procedure is to long

Answer 6

Just give a straight answer please help me solve this -The first term of a linear sequence is 5 and the common different is _3, find the 15th term of the sequence

Answer 7

pls I don't understand please help me with this the 8th if a linear sequence is 18 the 12 term is 26 find the first term the common difference and 20th term

Answer 8

I don't know

Answer 9

I don't understand

Answer 10

T15=a+14d
=5+14(-3)
=5+-42
=-37