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If the first dice yields an even number, what is the probability that the sum of the two dices will be equal to 12?

1st Die
P(even) = 3/6 = 0.50
P(6|even) = 1/3 = 0.333

2nd Die
P(6) = 1/6 = .1667

So P(12) = 0.5*0.33*0.1667 ?

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