If the expressed mass of AlCl³ to be formed is 3.5 g, what should be the initial mass of the pure aluminum metal

Answer 1

molar mass of AlCl₃ is 133 g

molar mass of Al is 27 g

3.5 g * (27 / 133) = ?

Answer 2

what is the answer?

Answer 3

0.71 g Al

Answer 4

Thank you