Applying law of conservation of energy:
P.E at height h = sum of translational and rotational K.E
mgh=1/2mv^2 +1/2Iw^2
but v=wr
I =moment of inertia.
=2/5mr^2
i hope u have get the concept Sarah
If the ball is released from rest at a height of 0.64 m above the bottom of the track on the no-slip side, what is its angular speed when it is on the frictionless side of the track?Assume the ball is a solid sphere of radius 4.0 cm and mass 0.14 kg
1 answer
1 answer