There are different ways to approach this problem, but one common method is to use the multiplication rule of probability, which states that the probability of two independent events both occurring is the product of their individual probabilities.
a) The probability of getting a 3 on a single spin is 1/6, since there are six equally likely outcomes. Assuming the spins are independent, the probability of getting two 3s in a row is the product of the probabilities of each spin: (1/6) x (1/6) = 1/36.
b) Similarly, the probability of getting a 4 on a single spin is 1/6, so the probability of two 4s in a row is (1/6) x (1/6) = 1/36.
c) To get a 1 followed by a 2, the arrow needs to land on 1 first and then on 2 on the second spin. The probability of getting a 1 on a single spin is 1/6, and assuming it happens, the probability of getting a 2 on the second spin is also 1/6. Therefore, the probability of getting a 1 followed by a 2 is (1/6) x (1/6) = 1/36.
d) To get a 4 followed by a 3, the arrow needs to land on 4 first and then on 3 on the second spin. The probability of getting a 4 on a single spin is 1/6, and assuming it happens, the probability of getting a 3 on the second spin is also 1/6. Therefore, the probability of getting a 4 followed by a 3 is (1/6) x (1/6) = 1/36.
If the arrow is spun twice, what is the probability of getting
a, two 3s
b, two 4s
c,a 1 followed by a 2
d,a 4 followed by a 3
1 answer
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