If the arrow in fig 11.5 on page 117 is spun twice,what is the probability of getting two 3s b two4s c a1 followed by a2 d 4 follow by a3?

Answer 1

In fig 11.5 on page 117, the arrow is divided into 6 equal sections labeled 1, 2, 3, 4, 5, and 6.

a) The probability of getting two 3s when the arrow is spun twice is the probability of getting a 3 on the first spin and a 3 on the second spin. Since there is only 1 section labeled 3 out of the 6 sections, the probability of getting a 3 on each spin is 1/6 * 1/6 = 1/36.

b) The probability of getting two 4s when the arrow is spun twice is the probability of getting a 4 on the first spin and a 4 on the second spin. Similarly, since there is only 1 section labeled 4 out of the 6 sections, the probability of getting a 4 on each spin is also 1/6 * 1/6 = 1/36.

c) The probability of getting a 1 followed by a 2 is the probability of getting a 1 on the first spin and a 2 on the second spin. Since there is only 1 section labeled 1 out of the 6 sections, the probability of getting a 1 on the first spin is 1/6. Similarly, since there is only 1 section labeled 2 out of the 6 sections, the probability of getting a 2 on the second spin is also 1/6. Thus, the overall probability is 1/6 * 1/6 = 1/36.

d) The probability of getting a 4 followed by a 3 is the probability of getting a 4 on the first spin and a 3 on the second spin. Since there is only 1 section labeled 4 out of the 6 sections, the probability of getting a 4 on the first spin is 1/6. Similarly, since there is only 1 section labeled 3 out of the 6 sections, the probability of getting a 3 on the second spin is 1/6. Thus, the overall probability is 1/6 * 1/6 = 1/36.