Compute the energy deposited in the body as heat in that time interval, and divide it by the heat capacity of the body.
The heat deposited is
(0.82)(501 W)(3600 s) = __ Joules
The heat capacity is (71.0 kg)(3480 J/kg C)= __ J/C
If the air temperature is the same as the temperature of your skin (about 30 degrees Celcius), your body cannot get rid of heat by transferring it to the air. In that case, it gets rid of the heat by evaporating water (sweat). During bicycling, a typical 71.0 kg person’s body produces energy at a rate of about 501 W due to metabolism, 82.0 percent of which is converted to heat. [Recall that the normal internal body temperature is 98.6 degrees Farenheit and the specific heat capacity of the body is 3480 J/(kg*degrees C)]. By how much would the body temperature of the bicyclist increase in an hour if he were unable to get rid of the excess heat?
2 answers
226200