4th term --- a + 3d
8th term ---- a + 7d
a+3d = 2(a+7d)
a+3d = 2a + 14d
-a = 11d
a = -11d
11th term = a + 10d
= -11d + 10d
= -d
10th term = a + 9d
= -11d + 9d
= -2d = twice -d = twice 11th term
If the 4th term of an A.P is twice the 8th term, prove that the 10th term is twice the 11th term.
2 answers
It's a wrong solution