If sound is increased in intensity by a factor of 100,000, what is the change in decibels?

Question

I thought 50?

other options are 5, 500, and 100,000. Please explain because I'm confused on how this works.

Answer 1

I thought 50 dB as well.

Answer 2

L(dB) = 10 log₁₀(P₁/P₀)= 10 log₁₀100000= =10•5=50

Answer 3

Thanks very much guys!!