If sin = 4/5 with A in QII, and sin B = -3/5 with B in QIV find cos(A-B)

Question

^Quen^ · Answer

cos(A-B)= cosAcosB+sinAsinB

If sinA = 4/5 in QII
draw you triangle in QII, and find the third side.
The third side is 3. (Do the same thing for sin B= -3/5
Plug in:
cosAcosB-sinAsinB
=(-3/5)*(4/5)+(4/5)*(-3/5)
=(-12/25) -(-12/25)
=-24/25

Anonymous · Answer

53. the longest side is 55 cm. find the length of the shortest side