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1molZnSO4= 164.46gZnSO4( the molar mass) 7.8 mol ZnSO4* (164.46gZnSO4/1molZnSO4) = 1259.388g ZnSO4
cos(A-B)= cosAcosB+sinAsinB If sinA = 4/5 in QII draw you triangle in QII, and find the third side. The third side is 3. (Do the same thing for sin B= -3/5 Plug in: cosAcosB-sinAsinB =(-3/5)*(4/5)+(4/5)*(-3/5) =(-12/25) -(-12/25) =-24/25
1mol =16 gO 2.40 mol O2* (32gO2/1molO2) =76.8gO2
First, find for m (slope): 3x-y=1 -y= 1-3x y=3x-1 , therefore m= 3 If lines in parallel to 3x-y=1, then the slopes are the same. So, plug in to equation . Y-Y2= m(X-X2) y-(-4)=3(x-2) y+4=3x-6 y=3x-10
Yea..I remembered now. Thanks 4 correcting !
well..I can't remember the formular for that one. But, you could figure it out by looking at equation. x^2-3x+(?) if you have to factor the equation, it will be like this: (x- ?) (x-?) Because of the middle number is -3x and the (?) is positive, it has to
If y varies directly with x, then there must be some number "k" such as: y=k*x Y = 12 when X = 3...So? 12=k*3 k=12/3 k=4 Since you found k, then you can plug in to find Y. Y= 4*16 Y= 64

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