If side of triangle are in the ratio 3:4:5 and its perimeter is 24 cm, find measure of each side of triangle. How to solve this Questions please show.
9 answers
6 cm,8 cm,and 10 cm
pata nahi hai please answer Bata dijiye
3+4+5 = 12
You want their sum to be 24, so double each value.
You want their sum to be 24, so double each value.
let the sides be 3x, 4x, and 5x
3x+4x+5x = 24
12x = 24
x = 2
sub back into my definitions of the sides
so the sides are 6, 8, and 10
3x+4x+5x = 24
12x = 24
x = 2
sub back into my definitions of the sides
so the sides are 6, 8, and 10
You want their sum double each value see 👇
3×2=6,4×2=8,5×2=10
3×2=6,4×2=8,5×2=10
Let the sides be 3x , 4x , 5x ..
3x +4x+5x=24
12x=24
X = 24/12
=2
3 X 2 =6
4 X 2=8
5 X 2 =10
Thank you hope this will help
3x +4x+5x=24
12x=24
X = 24/12
=2
3 X 2 =6
4 X 2=8
5 X 2 =10
Thank you hope this will help
6,8,10
A=3x
B=4x
C=5x
Perimeter=a+b+c=24cm
=3x+4x+5x=24cm
=12x=24cm
=x=24/12=2cm
=x=2cm.
=A=3x=3×2=6
=B=4x=4×2=8
=C=5x=5×2=10
S(semi perimeter) = a+b+c/2
S(semi perimeter) =6+8+10/2
=24/2=12.
∆=√S(s-a)(s-b)(s-c)
=√12(12-6)(12-8)(12-10)
=√12×6×4×2
=√576
=24cm^2
Name=Gaurav
Class=9th
Thank you 😊
B=4x
C=5x
Perimeter=a+b+c=24cm
=3x+4x+5x=24cm
=12x=24cm
=x=24/12=2cm
=x=2cm.
=A=3x=3×2=6
=B=4x=4×2=8
=C=5x=5×2=10
S(semi perimeter) = a+b+c/2
S(semi perimeter) =6+8+10/2
=24/2=12.
∆=√S(s-a)(s-b)(s-c)
=√12(12-6)(12-8)(12-10)
=√12×6×4×2
=√576
=24cm^2
Name=Gaurav
Class=9th
Thank you 😊
Question:Find the perimeter of a regular hexagon with each side measuring 4m?......ANSWER ...draw a hexagon with each side measuring 4m therefour perimeter of hexagon equal to (sum of all sides) which implies that ..4+4+4+4+4+4 equal to( 24cm) answer