If one pound (454g) of hexane combusts with 185 grams of oxygen which reactant is the limiting reactant and how many grams of carbon dioxide are produced?

Question

My work: 454 g C6H14 * 1 mol C6H14/86.18 g C6H14 * 6 mol CO2/ 1 mol C6H14 * 44 g C02/ 1 mol CO2= 1390.7 g/ CO2

185 g O2 * 1 mol O2/ 32 g O2 * 6 mol CO2/(19/2) mol O2 * 44 .0g CO2/ 1 mol CO2= 160.65 g/CO2

Limiting factor is O2

Answer 1

The process looks ok to me but you have too many significant figures in the answer. I would round that to 161 grams.