If Mike has 8 dimes and 6 pennies in his pocket. If he randomly selected one coin and then a second coin without replacing the first, what is the probability that both coins were dimes?

Question

If Mike has 8 dimes and 6 pennies in his pocket.  If he  randomly  selected one coin and then a second coin without replacing the first, what is the probability that both coins were dimes?

Reiny · Answer

prob(2dimes) = (8/14)(7/13) = 4/13

BOLAJI Oretan · Answer

Probability of choosing the first coin (dime) = 8/14 Probability of choosing the second without replacement = 7/13 Probability of choosing the first AND second = (8/14)(7/13)=4/13