If log10(2x+1)-log10(3x-2)=1 find x.

Answer 1

If the base of your log is 10, you may skip writing it
log(2x+1)-log(3x-2)=1
log [(2x+1)/(3x-2)] = 1
by definition:
(2x+1)/(3x-2) = 10^1 = 10
30x - 20 = 2x+1
28x = 21
x = 21/28 = 3/4

Answer 2

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Answer 3

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Answer 4

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Answer 5

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