If θ is an angle in standard position and tan θ = −7/2, in which quadrant can θ be located?

Answer 1

by definition tan θ = y/x
y/x = -7/2 <----- y is negative, x is positive, so quadrant IV
or
y/x = 7/-2 <---- y is positive, x is negative, so quadrant II

Find out about a very useful rule called the CAST rule, which
tells you where the 3 main trig ratios are positive.
Very hard to do any of these questions without knowing that rule.

Answer 2

since tan θ = y/x, x and y must have different signs.
QII, QIV