The velocity is represented by the first derivative of h(t)
so h'(t) = -32t + 13
you want that to be zero
so
-32t + 13 = 0
t = 13/32 seconds
plug that into the original and you are done
if h(t) represents the height of an object above ground level at time t and h(t) is given by h(t)=-16t^2+13t+1.
find the height of the object at the time whent eh speed is zero
1 answer
1 answer