you fill t with 0
so 0-2-1=-3
if it said find g(t)=6
1/6-2-1=-17/6
If g(t)= 1/t-2-1,
how to solve g(t)=0 ...?
Please teach me..!
4 answers
I disagree with what Christos did
it said solve g(t) = 0 , not find g(0)
First of all I am sure you meant:
g(t) = 1/(t-2) - 1
so if g(t) = 0,
1/(t-2) - 1 = 0
1/(t-2) = 1
t - 2 = 1
t = 2
it said solve g(t) = 0 , not find g(0)
First of all I am sure you meant:
g(t) = 1/(t-2) - 1
so if g(t) = 0,
1/(t-2) - 1 = 0
1/(t-2) = 1
t - 2 = 1
t = 2
It isn't t=3 ..?
Thanks for answers!!