If g(t)= 1/t-2-1,

how to solve g(t)=0 ...?

Please teach me..!

4 answers

you fill t with 0

so 0-2-1=-3

if it said find g(t)=6

1/6-2-1=-17/6
I disagree with what Christos did
it said solve g(t) = 0 , not find g(0)

First of all I am sure you meant:
g(t) = 1/(t-2) - 1
so if g(t) = 0,
1/(t-2) - 1 = 0
1/(t-2) = 1
t - 2 = 1
t = 2
It isn't t=3 ..?
Thanks for answers!!
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