use the chain rule.
If y = f(u) and u is a function of x, then
dy/dx = dy/du * du/dx
so, in this case,
f = 6lnu
u = 6x + 3lnx
f'(x) = 6/u * du/dx = 6/(6x + 3lnx) * (6 + 3/x) = 54(2x + lnx)(2 + 1/x)
If f(x) =6ln(6x+3ln(x))
How do I Find the first derivative
1 answer
1 answer