If f(x)=3x^2 g(x)= 1/6+x find the following and give the domain

(f+g) (x) (3x^2) + (1/6+x) x is all real numbers and x is not equal to 6
(f-g) (x) (3x^2) - (1/6+x) 3x^2 -6-x x is all real numbers and x is not equal to -6
(f x g) (x) I do not understand
(f/g) (x) 3x^2/6-x x is all real numbers and x is not equal to 6

Similar Questions
    1. answers icon 2 answers
    1. answers icon 1 answer
  1. f(x)=v^2+13/v^2-4v-32Find all numbers that are not in the domain of the function. Then give the domain in set notation.
    1. answers icon 2 answers
  2. Ok I got another one I can figure outThe one-to-one function f is defined by f(x)=(4x-1)/(x+7). Find f^-1, the inverse of f.
    1. answers icon 2 answers
more similar questions