c = a + b t
30 = a + 2 b
50 = a + 6 b
--------------------- subtract
-20 = -4 b
b = 5
30 = a + 10
a = 20
so
c = 20 + 5 t
so now you finish
If c is partly constant and partly varies to t find the relation between c and t if c equal to 30 when t equal to 2 and c equal to 50 when t equal to 6 find c when t equal to 3
3 answers
c = mt + k
when c = 30, t = 2, c = 50
but you already told me that c = 30
the rest is"
" and c equal to 50 when t equal to 6 find c when t equal to 3"
which is a lot of gobbledegook.
So I will wait till you fix the problem
when c = 30, t = 2, c = 50
but you already told me that c = 30
the rest is"
" and c equal to 50 when t equal to 6 find c when t equal to 3"
which is a lot of gobbledegook.
So I will wait till you fix the problem
ahh, looks like Anonymous
figured out what you were saying , go with his solution
figured out what you were saying , go with his solution