If an object orbiting the Sun sweeps out of an area of A in a time t1 at the closet point of the object's orbital rotation. How much area does the object sweep out at the farthest point of the object's orbit t2?

Answer 1

According to Kepler's second law of planetary motion, the object sweeps out equal areas in equal time intervals. Therefore, the object will sweep out the same area A at both the closest and farthest points of its orbit.