If an object orbiting the Sun sweeps out an area of A in a time t1 at the closest point of the object’s orbital rotation. How much area does the object sweep out at the farthest point of the object’s orbit, t2?

Question

a
2A
b
A
c
1/2A
d
A^2

Answer 1

The correct answer is b) A.

The area swept out by an object in a given time is proportional to the time spent and the orbital speed of the object. Since the distance between the object and the Sun is the same at both the closest and farthest points of the orbit, the time spent at each point is the same.

Therefore, the object will sweep out the same amount of area at both the closest and farthest points of its orbit.