Vo = 30mi/h = 30*5280Ft/3600s = 44 Ft/s
V^2 = Vo^2 + 2g*h = 0
h = -Vo^2/2g + ho = -(44^2)/-64 + 160 =
190.25 Ft above gnd.
V^2 = Vo^2 + 2g*h = 0 + 64*190.25 =
12,176
V = 110.3 Ft/s.
If an object is thrown in an upward direction from the top of a building 160 ft high at an initial speed of 30 mi/h, what is its final speed when it hits the ground
1 answer