d = Vo*t + 0.5g*t^2,
d = 10*3 - 5*3^2 = -15m. = 15m below the top of building.
An objectis thrown upward from the edge of a tall building with a velocity of 10m/s. Where will the object be 3s after it is thrown? Take g = 10m/s^2
15m above the top of the building
30m below the top of the building
15m below the top of the building
30m above the building
2 answers
What is the gravitation field strength of a height above the surface of the earth? R is the radius of the earth. Ans a, pls correct
13 answers