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If an object is dropped from a height of 200 feet, the function h(t) = -16 t^2 + 200 gives the height of the object after t seconds. Approximately, when will the object hit the ground?

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h(t) = -16 t^2 + 200

Ground = 0 feet

0 = -16 t^2 + 200

Solve for t.

0 = 200 -16 t^2
16 t^2 = 200
t = sqrt (25/2) =3.544 seconds

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