If an aquarium tank holds 100 litres of water, calculate how much heat energy would be required to heat the tank from 18.2 Degrees(C) to 32 Degrees(C)
4 answers
I cant for the life of me figure out how to complete this question as our teacher hasn't properly gone over this section.
If you assume the density of water is 1.00 g/mL, then 1000 L H2O will have a mass of 1000 grams.
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
To clarify, 100 L weigh 100 kg or 1x10^5 g
Yes and I'm pleased that you caught that (those) typos.
100 L is 100E3 mL and
100E3 mL x 1.00 g/mL = 1E5 g.
100 L is 100E3 mL and
100E3 mL x 1.00 g/mL = 1E5 g.